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Math 30-1 · Exponents and logs

Exponents and logarithms

A logarithm is just a question: "what exponent do I need?" Once that clicks, the laws stop looking like rules to memorise and start looking obvious.

Exponential and log graphs

The idea: y = bˣ and y = logb x are inverses, so their graphs are reflections of each other in the line y = x.

y = 2ˣ y = log₂ x y = x (0, 1) (1, 0)
Swapping x and y turns one into the other: (0, 1) on y = 2ˣ becomes (1, 0) on y = log₂ x.
y = bˣy = logb x
Domainall real numbersx > 0
Rangey > 0all real numbers
Intercept(0, 1)(1, 0)
Asymptotehorizontal, y = 0vertical, x = 0

When b > 1 the exponential grows; when 0 < b < 1 it decays. Transformations work the way they always do: y = log(x − 2) moves the asymptote to x = 2, so its domain is x > 2.

What a logarithm actually is

The idea: logb x = y means exactly the same thing as by = x. The log is the exponent.

Read log₂ 8 as "2 to what power gives 8?" The answer is 3. Every evaluation works this way:

  • log 1000 = 3, because 10³ = 1000 (no base written means base 10)
  • log₅ 1 = 0, because anything to the power 0 is 1
  • log₃(1/9) = −2, because 3⁻² = 1/9
  • logb b = 1, always

Watch out: you cannot take the log of zero or a negative number. No power of a positive base ever gives you one.

The laws of logarithms

The idea: logs turn multiplying into adding, dividing into subtracting, and powers into multipliers — because that is exactly what exponents do.

LawRuleExample
Productlog(MN) = log M + log Nlog 25 + log 4 = log 100 = 2
Quotientlog(M/N) = log M − log Nlog₂ 12 − log₂ 3 = log₂ 4 = 2
Powerlog(Mⁿ) = n log M2 log 5 = log 25
Change of baselogb x = log x ÷ log blog₃ 20 = log 20 ÷ log 3 ≈ 2.73

Writing logs in terms of other logs

If log 2 = a and log 3 = b, then log 12 = log(2² × 3) = 2 log 2 + log 3 = 2a + b. Break the number into factors you know, then apply the laws.

Watch out: log(M + N) is not log M + log N, and log M ÷ log N is not log(M/N). The laws only work in the shapes shown above.

Solving equations and real-world models

The idea: if you can make the bases match, match the exponents. If you cannot, take the log of both sides.

Method 1: common base

4ˣ⁺¹ = 8ˣ. Both are powers of 2: 2²⁽ˣ⁺¹⁾ = 2³ˣ. Now the exponents must be equal: 2x + 2 = 3x, so x = 2.

Method 2: take logs

3ˣ = 20 has no common base. Take the log of both sides: x log 3 = log 20, so x = log 20 ÷ log 3 ≈ 2.73. Sanity check: 3² = 9 and 3³ = 27, so the answer must be between 2 and 3.

Log equations: always check

log₂ x + log₂(x − 2) = 3 combines to x(x − 2) = 2³ = 8, which gives x = 4 or x = −2. But log₂(−2) is undefined, so −2 is extraneous. The only solution is x = 4.

The models you will see

  • Growth and decay: A = A₀(b)t/p, where p is how long one doubling or halving takes. 80 g with a 5-year half-life after 15 years: 80(½)³ = 10 g.
  • Compound interest: A = P(1 + i)ⁿ. To double $1000 at 6%: 2 = 1.06ⁿ, so n = log 2 ÷ log 1.06 ≈ 11.9 years.
  • Log scales: Richter, pH and decibels go up by a factor of 10 per step. Magnitude 7 is 10² = 100 times as intense as magnitude 5.

Watch out: on a log scale, a difference of 2 means 100 times, not twice. The number on the scale is the exponent.

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